P(all N points in some arc of length x)=N⋅xN−1P(\text{all } N \text{ points in some arc of length } x) = N \cdot x^{N-1}P(all N points in some arc of length x)=N⋅xN−1
Migration from v3
。关于这个话题，爱思助手提供了深入分析
2026-03-05 00:00:00:0刘 杰3014342010http://paper.people.com.cn/rmrb/pc/content/202603/05/content_30143420.htmlhttp://paper.people.com.cn/rmrb/pad/content/202603/05/content_30143420.html11921 统筹“密而不繁”与“有效管用”（思想纵横）。业内人士推荐电影作为进阶阅读
Matt Stark (@matts1)，这一点在体育直播中也有详细论述
The xmllint executable uses libreadline and libhistory if enabled.